Mofor's school is selling tickets to the annual dance competition. on the first day of ticket sales the school sold 7 adult tickets and 6 tickets for a total of $143. the school took in $187 on the second day by selling 4 adult tickets and 13 student tickets. find the price of an adult ticket and the price of a student ticket.

the price of an adult ticket is $11

the price of a child ticket is $11

Step-by-step explanation:

Let x represent the price of an adult ticket.

Let y represent the price of a student ticket.

On the first day of ticket sales the school sold 7 adult tickets and 6 student tickets for a total of $143. This means that

7x + 6y = 143 - - - - - - - - - -1

The school took in $187 on the second day by selling 4 adult tickets and 13 student tickets. This means that

4x + 13y = 187 - - - - - - - - - -2

Multiplying equation 1 by 4 and equation 2 by 7, it becomes

28x + 24y = 572

28x + 91y = 1309

Subtracting

-67y = -737

y = -737/-67 = 11

Substituting y = 11 into equation 1, it becomes

7x + 6×11 = 143

7x + 66 = 143

7x = 143 - 66 = 77

x = 77/7 = 11

true

step-by-step explanation: