Can someone list the amount of numbers that have a gcf of 7 and a product of 490?

The amount of numbers that have a G C F of 7 and a product of 490 is 2.

Step-by-step explanation:

On Prime Factorization 490   =   2   x   5   x   7   x   7

G CF = Greatest Common Factor

So, here the possible number who have products as 490 and G C F as 7 is

(a)  2 x 7 = 14  and   5 x 7  = 35

As, 14 and 35 on multiplication,gives 490 as a  product.

And, G C F  of 14 and 3 5 is also 7.

(b)  7  and   5 x 7 x  2  = 70

As, 7 and 70 on multiplication,gives 490 as a  product.

And, G C F  of 7  and 70 is also 7.

⇒ (14, 35) and (7,70) are the only such pairs.

Hence, the amount of numbers that have a G C F of 7 and a product of 490 is 2.

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: