Quadrilateral mnpq has vertices m(0,6), n (4,4), p (6, -1), and q (2.0). determine the coordinates of the vertices of the image of the
quadrilateral after the translation (x, y) → (-1, y + 5)

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.

cool? what is the actuall ?

step-by-step explanation:

answer: the answer for that is 22/3