Suppose the scores of students on a statistics course are normally distributed with a mean of 563 and a standard deviation of 37. what percentage of the students scored between 563 and 637 on the exam?

47.72% of students scored between 563 and 637 on the exam .

Step-by-step explanation:

The percentage of the students scored between 563 and 637 on the exam

= The percentage of the students scored lower than 637 on the exam -

the percentage of the students scored lower than 563 on the exam.

Since 563 is the mean score of students on the Statistics course, 50% of students scored lower than 563. that is P(x<563)=0.5

P(x<637)=P(z<z*) where z* is the z-statistic of the score 637.

z score can be calculated using the formula

z*= where

Then z*= =2

P(z<2)=0.9772, which means that 97.72% of students scored lower than 637 on the exam.

As a Result, 97.72%-50%=47.72% of students scored between 563 and 637 on the exam

its 69.420

step-by-step explanation:

this is false ^.^ lol