What is the equation of the line that has a slope of -4 and goes through (-1,6)?
a. y + 6 = -4(x + 1)
b.
y + 6 = -4(x - 1)
c.
d.
y-6 = -4(x + 1)
y - 6 = -4(x - 1)

y-6=-4(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=-4

y-6=-4(x-(-1))

y-6=-4(x+1)

C. y − 6 = -4(x + 1)  

Step-by-step explanation:

I got it right in a test.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

29.5977692753

step-by-step explanation: