99 points will give no fake answers!
keyshawn is bowling in a competition. he has a 26% chance of getting a strike each time he bowls. what is the probability that keyshawn doesn't get a strike until after his first five attempts?
a) 0.19
b) 0.22
c) 0.78
d) 0.85

the probability of coram making a free throw is 77%. what is the probability that he makes his first free throw within his first two shots?
a) 79%
b) 83%
c) 88%
d) 95%

He has a 26% of getting a strike, which means he has a 74% chance of not getting a strike ( 100% - 26% = 74%).

Multiply the chance of not getting a strike by the number of attempts:

0.74 x 0.74 x 0.74 x 0.74 x 0.74 = 0.22

The answer is B) 0.22

The probability of making a free throw is 77%, the probability of not making one would be 23% ( 100% - 77% = 23%).

Add the probability of making the first one ( 0.77) by the probability of making the second one multiplied by the probability of missing the second one ( 0.77x 0.23)

0.77 + (0.77 x 0.23)

0.77 + 0.18 = 0.95

The answer is D) 95%

37 = ending with 7

unit's digit in the cube..3

56 = ending with 6

unit's digit in the cube..2

133 = ending with

unit's digit in the cube..7

hope it : ( : )

im not sure what this means: mc011-7.jpg

step-by-step explanation: