Jake tosses a coin up in the air and lets it fall to the ground. the equation that models the height (in feet) and time (in seconds) of the parabola is h(t)= -16t^2+ 24t+6. what is the height of the coin when jake tosses it?

The maximum height of coin Jake tosses is 15 feet.

Step-by-step explanation:

Given Jake tosses a coin up in the air

and the height of coin is model by h(t)=

To find height of the coin when Jake tosses it:

When a coin is in the hand of Jake, time t=0

Height of coin is h(t)=

h(0)=

h(0)=6 feet.

Therefore, Height of coin at time t=0 is 6.

For maximum height of the coin,

h(t)=

Differentiating both side,

t=

t=

t=0.75

Now,

h(t)=

h(0.75)=

h(0.75)=15 feet.

The maximum height of coin jake tosses is 15 feet.

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.