Asystem of equations is shown below: 2x = −y + 6 −4x + 3y = 8 what is the solution to this system of equations?
(−1, −4)
(1, 4)
(4, 1)
(−4, −1)
me!
also explain how to get it.

2x = -y + 6 i.e. 2x + y = 6 . . . . . . . . (1)
-4x + 3y = 8 . . . . . . . . (2)
From (1), y = 6 - 2x . . . . . . . . (3)
substituting the value of y into equation (2), we have,
-4x + 3(6 - 2x) = 8
-4x + 18 - 6x = 8
-10x + 18 = 8
-10x = 8 - 18 = -10
x = -10/ -10 = 1
substituting the value of y into equation 3, we have,
y = 6 - 2(1) = 6 - 2 = 4
Therefore, the solution is (1, 4).

The answer to your question is the last one