Need solving with working much appreciated

i. g = 70°

ii. x = 85°

Step-by-step explanation:

Given:

Let first we name the triangle

i. ) Δ PQR , m∠ PRQ = 40°

ii. ) Δ ABC is a right angle at B and a line B- D-C

       m∠ DAC = 25°

       m∠ ACD = 60°

       m∠ BDA = x°

To Find:

i. g = ?

ii. x = ?

Solution:

i.

In Δ PQR , PR ≅ QR ...........{Given]

∴ Δ PQR is an Isosceles Triangle.

c.........{ Base angles of Isosceles triangle are equal }

∴ m∠ PQR = m∠ RPQ = g

Now sum of all the angles in a triangle is 180°

∴ m∠ PQR + m∠ RPQ + m∠ PRQ = 180°....{Angle sum property of Triangle}

∴ g = 70°

ii.

We know sum of all the angles in a triangle is 180°

In Δ DAC

m∠ DAC + m∠ ACD + m∠ ADC = 180°.....{Angle sum property of Triangle}

Now By Linear Pair Angle Property

m∠ ADB + m∠ ADC = 180° ........{Linear Pair Angle Property}

∴ x = 85°

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72