The amount of filling in a doughiest donut boston cream donut follows a normal distribution, with a mean of 3 ounces and a standard deviation of 0.4 ounce. a random sample of 36 donuts is selected every day and measured. what is the probability the mean weight will exceed 3.1 ounces?

The probability the mean weight will exceed 3.1 ounces is 0.0668

Step-by-step explanation:

We have a random sample of size n = 36 measures which comes from a normal distribution with a mean of 3 ounces and a standard deviation of 0.4 ounces. Then, we know that the mean weight is also normally distributed with the same mean of 3 ounces and a standard deviation of . The z-score associated to 3.1 is (3.1-3)/(0.4/6) = 1.5. We are looking for P(Z > 1.5) = 0.0668, i.e., the probability the mean weight will exceed 3.1 ounces is 0.0668

3.1 ounces is 0.0668

Step-by-step explanation:

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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