Nolan began a savings account three years ago. he invested $100 at a 2% interest rate according to the equation vn = 100(1.02)x, where vn is the value of his account after x years. anias started an account today. she invested $100 at a 2% interest rate according to the equation va = 100(1.02)x–3, where va is the value of her account. let’s say anias started saving at the same time nolan did, three years ago. approximately how much money would she have had to invest to have the same amount of money she has now?
$5.77
$90.24
$94.23
$106.12

answer: options?

step-by-step explanation:

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752