Euben's coffee shop makes a blend that is a mixture of two types of coffee. type a coffee costs reuben $5.70 per pound, and type b coffee costs $4.30 per pound. this month, reuben made 167 pounds of the blend, for a total cost of $820.30. how many pounds of type a coffee did he use?

The quantity of type A coffee is 73 pounds

The quantity of type B coffee is 94 pounds .

Step-by-step explanation:

Given as :

The price of Type A coffee costs = $ 5.70 per pound

The price of Type B coffee costs = $ 4.30 per pound

The total quantity of coffee does Reuben purchases = 167 pounds

The total cost of the coffee for 167 pounds = $ 820.30

Let The quantity for type A coffee = a pounds

And The quantity of type B coffee = b pounds

Now, According to question

a + b = 167 pounds      And

$ 5.70 × a + $ 4.30 × b = $ 820.30

Now solving equations

5.70 × ( a + b ) = 5.70 × 167

or, 5.70 a + 5.70 b = 951.9

Now ,

( 5.70 a + 5.70 b ) - (   5.70  a +  4.30  b ) = 951.9 - 820.30

or, ( 5.70 a - 5.70 a ) + ( 5.70 b - 4.30 b ) = 131.6

Or, 0 + 1.4 b = 131.6

∴ b =

I.e b = 94 pounds

Put the value of b to get a value

So, a = 167 pounds - b

Or, a = 167 - 94

∴   a = 73 pounds

Hence The quantity of type A coffee is 73 pounds

And The quantity of type B coffee is 94 pounds   .  Answer

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question