Aphysics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. if an examinee must answer 6 of the multiple-choice questions and 4 of the open-ended problems, in how many ways can the questions and problems be chosen?

a) 1260
b) 1296
c) 261,273,600
d) 21,772,800

A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

=

No. of ways to answer 4 open-ended problems

=

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

=

Hence, the correct answer is option A) 1260

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: