if f(x) = x - 5, then match each of the following.

click the item in the left column. use the plus sign to move it up or the minus sign to move it down until it matches the correct entry in the right column. lock your answer in place by clicking the square beside the item. (a checkmark means it is locked.)

0 f(-1)
-4 f(0)
-5 f(1)
3 f(2)
-6 f(5)
-3 f(8)

f(-1) = -6

f(0) = -5

f(1) = -4

f(2) = -3

f(5) = 0

f(8) = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

FunctionsFunction Notation

Step-by-step explanation:

Step 1: Define

Identify

[Function] f(x) = x - 5

f(-1) is x = -1 for function f(x)

f(0) is x = 0 for function f(x)

f(1) is x = 1 for function f(x)

f(2) is x = 2 for function f(x)

f(5) is x = 5 for function f(x)

f(8) is x = 8 for function f(x)

Step 2: Evaluate

f(-1)

Substitute in x [Function f(x)]:                                                                          f(-1) = -1 - 5Subtract:                                                                                                            f(-1) = -6

f(0)

Substitute in x [Function f(x)]:                                                                          f(0) = 0 - 5Subtract:                                                                                                            f(0) = -5

f(1)

Substitute in x [Function f(x)]:                                                                          f(1) = 1 - 5Subtract:                                                                                                            f(1) = -4

f(2)

Substitute in x [Function f(x)]:                                                                          f(2) = 2 - 5Subtract:                                                                                                            f(2) = -3

f(5)

Substitute in x [Function f(x)]:                                                                          f(5) = 5 - 5Subtract:                                                                                                            f(5) = 0

f(8)

Substitute in x [Function f(x)]:                                                                          f(8) = 8 - 5Subtract:                                                                                                            f(8) = 3

Its d so thats how it would would back from 1.0 form three four two

Dis the answer for this question