20 points need asap

which statements describe the end behavior of the graph of the function shown? check all that apply.

f(x)=(x-2)(x+1) /x+1

a as x → ∞, y → 1.

b as x → ∞, y → ∞.

c as x → ∞, y → –∞.

d as x → –∞, y → 1.

e as x → –∞, y → ∞.

f as x → –∞, y → –∞

check all that apply

There are 2 answers: choice B and choice F

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Explanation:

Assuming the second "x+1" is all in the denominator, this will cancel with the first "x+1" in the numerator. I'm using the rule that x/x = 1 where x is nonzero.

What happens after the canceling is that f(x) = x-2. This is a linear equation with positive slope (the slope is 1).

The positive slope means the line goes up as we read it from left to right. As x gets larger, y does too. So we can say

Going in reverse, as x heads off to negative infinity, y does the same as well. Therefore,

Below is the graph attached as an image to help visually verify the two answers. Note the hole at x = -1 which is due to the fact that this x value makes the original unsimplified version of f(x) to be undefined. Recall that we cannot divide by zero so x+1 cannot be equal to zero.

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation: