Can someone me answer this question attached.

see the explanation

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal angles

step 1

Find the measure of angle BDA

we know that

Triangle ABD is an isosceles triangle

AB=AD ---> given problem

so

m∠ABD=m∠BDA

therefore

m∠BDA=72°

step 2

Find the measure of angle BAD

Remember that the sum of the interior angle in a triangle must be equal to 180 degrees

In the triangle BDA

m∠ABD+m∠BDA+m∠BAD=180°

substitute the given values

72°+72°+m∠BAD=180°

144°+m∠BAD=180°

m∠BAD=180°-144°=36°

step 3

Find the measure of angle BCA

In the triangle ABC

m∠BCA=m∠BAC

we have that

m∠BAC=m∠BAD=36°

therefore

m∠BCA=36°

step 4

Find the measure of angle ABC

In the triangle ABC

m∠BAC+m∠BCA+m∠ABC=180°

substitute the given values

36°+36°+m∠ABC=180°

72°+m∠ABC=180°

m∠ABC=180°-72°=108°

step 5

Find the measure of angle DBC

we know that

m∠DBC+m∠ABD=m∠ABC ----> by addition angle postulate

substitute the given values

m∠DBC+72°=108°

m∠DBC=108°-72°=36°

step 6

Find the measure of angle BDC

we know that

m∠BDC+m∠ADB=180° ----> by supplementary angles

substitute the given value

m∠BDC+72°=180°

m∠BDC=180°-72°=108°

step 7

In the triangle DBC we have

m∠DBC=36°

m∠BCD=m∠BCA=36°

so

The triangle BCD has two equal angles

therefore

Triangle BCD is an isosceles triangle

and

BD=BC

answer: the answer is 127 degrees

i dont get the question

step-by-step explanation: