You want to plot the collinear points a(-2,3), a'(x, y), and a"(3,7) on the same coordinate plane. find the values of x and y.

Step-by-step explanation:

Remember that three points are collinears if they stay in the same line.

To find the line that pass through A(-2,3) and A''(3,7), we find first the slope of the line and then the y-intercept.

The slope of the line is

The y-intercept of the line is

Then the equation of the line is

Since we want that the point A'(x,y) stay in the line, then we need to choose a value for x and replace in the equation found.

If we take x=2

Then the points   are collinear.

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)