Kent has a bag with 8 blue marbles, 6 red marbles, and 6 green marbles in it. if he draws two marbles out of the bag one at a time without replacement, what is the probability that both marbles will be blue?

a. 1/10
b. 7/50
c. 14/95
d. 4/25
e. 16/95

C) The probability of drawing two blue marbles without replacement  is

Step-by-step explanation:

Total number of blue marbles  = 8

Total marbles = Number  of ( Blue + Red + Green) marbles

                        = 8+ 6 + 6 = 20 marbles

Now,Let  E: Event of picking a blue marble

Also, we know that P (any Event E) =

⇒ P( Picking first Blue marble) =

Now, again P( Picking second Blue marble) =

Again , P( Drawing two blue marbles without replacement)

= P( Picking first Blue marble)  x P( Picking second Blue marble)

Hence, the probability of drawing two blue marbles without replacement from the bag is

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get