Suppose the diameter at breast height (in.) of trees of a certain type is normally distributed with 8.8 and 2.8, as suggested in the article "simulating a harvester-forwarder softwood thinning" (forest products). a. what is the probability that the diameter of a randomly selected tree will be at least 10in.? will exceed 10in.?

b. what is the probability that the diameter of a randomly selected tree will exceed 20in?

c. what is the probability that the diameter of a randomly selected tree will be between 5 and 10in.?

d. what value c is such that the interval (8.8 − c, 8.8 + c) includes 98% of all diameter values?

e. if four trees are independently selected, what is the probability that at least one has a diameter that exceeds 10in.?

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct

answer: the answer is   graph (a)

all you should have to do is insert 1 where the c is, representing that one car is sold.

f(c) = 250c + 500

f(1) = 250(1) + 500

f(1) = 250 + 500

f(1) = 750

he earns $750 for each car sold.

hope this you! have a happy , here's a turkey!