Adrop set of 20 gtt/ml is used to run a liter of fluid at 50 gtt/min. how long will it take for the liter to run out?

400 Minutes

Step-by-step explanation: 20 gtt/mL ÷ 50 gtt/min

⇒ 20/50 (gtt/gtt)(min/mL)

= 2/5 min/mL.

For a liter to run out it will take

⇒ 2/5 × 1000 = 400 minutes

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.