Chris has $3.30 in nickels and quarters. if she has twice as many quarters as nickels, how many of each coin does she have?

Chris has 12 quarters and 6 dimes

Step-by-step explanation: Lets have x be the number of quarters and y be the number of nickels. If she has twice as many quarters as nickels, then we already have our first equation: x=2y! To get the second equation, you put the real world value of quarters and nickels next to their variable and have it equal the total amount of money she has ($3.30), so the equation should look like this:

.25x + .05y=3.30

The next step is easy, just solve by substituting the equations into each other! So:

If x= 2y then,

.25(2y) + .05y= 3.30

.5y + .05y= 3.30

(.55y= 3.30)÷ .55

y= 6

And if y (which is the number of nickels!) equals 6, then we can plug that back into the x= 2y equation! So:

x= 2(6)

x= 12

Thus, Chris has 12 quarters and 6 nickels! Hope this helps!

/

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation