(4)

the ratio of cockles to winkles in a bag of

sea shells is 1: 2

when 6 winkles are accidentally spilt from

the bag the ratio is 3: 5

how many of each shell were there

initially?

Step-by-step explanation:

Let the number of cockles be c and that of winkles be w.

From the first relation,

w = 2c (I)

From the second relation, 6 winkles are accidentally split.

This in equation form means the following:

c/w- 6 = 3/5

By cross multiplication,

5c = 3(w - 6)(ii)

We know w = 2c , let’s substitute this into the second equation.

5c = 3(2c - 6)

5c = 6c - 18

Collecting like times, c = 18

And w = 2c = 2(18) = 36

Hence, there were initially 18 cockles and 36 winkles

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm