Which function's graph has a period of 2?
y=cos(x-pi/2)
y=3cos pi x
y=2 sin 3x
y=-4 sin 2x

Option 2. y = 3 cos πx is the answer.

Step-by-step explanation:

If the function is in the standard form of y = acos(bx+c)  or y = asin(bx+c)

Then period of the given function will be = 2π/b

1) For y = cos(x - π/2)

Therefore period of the function will be = 2π/1 = 2π

2) For y = 3cos πx

Period = 2π/π = 2

Correct option.

3) y = 2 sin 3x

Period of the function = 2π/3

4). y = -4sin 2x

Period of the function = 2π/2 = π

So option 2 is the answer.

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.