Asimple random sample of 100 bags of tortilla chips produced at plant a is selected every hour for quality control. in the current sample, 18 bags had more chips (measured in weight) than the labeled quantity. this sample information is being compared to data collected at plant b. in the current sample of 100 bags of chips from plant b, 12 bags had more chips than the labeled quantity. what is the relative risk that a bag of tortilla chips produced at plant a had more chips than the labeled quantity as compared to plant b?

Relative Risk = 1.5, so there is a positive association between the two groups so is likely to happen that Plant A has more chips than the labeled quantity as compared to Plant B

Step-by-step explanation:

The relative risk measuers the relationship between the risk group (Plant A) and the reference group (Plant B)  in order to compare the  probability of an event occurring in one group compared to the other.

It is  calculated by dividing the probability of the event occurring for PLANT A divided by the probability of the same event occurring for PLANT B:

Probability for PLANT A = 18/100 = 0.18

Probability for PLANT B = 12/100 = 0.12

So RR= 0.18/0.16= 1.5

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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