For f(x) = 3x+1 and g(x) = x2 - 6, find (f - g)(x).
o a. 3x² - 17
o b. x2 – 3x-7
o c. -x2+3x+7
o d. - x2 + 3x - 5

For f(x) = 3x+1 and g(x) = x^2 - 6, find (f - g)(x)

O A. 3x² - 17

O B. x^2 – 3x-7

O C. -x^2+3x+7

O D. - x^2 + 3x - 5

Option C

For f(x) = 3x+1 and g(x) = x^2 - 6 then the value of

Given that,

To find:  (f - g)(x)

We know that,

(f – g)(x) = f (x) – g(x)

Let us substitute the given values of f(x) and g(x) to find (f – g)(x)

On multiplying the negative sign with terms inside second bracket

On rearranging the terms we get,

Thus the value of (f - g)(x) is found out and option C is correct

linear pair postulates

the radius is 2 times the diameter.

step-by-step explanation: