Use the given information to find the number of degrees of freedom, the critical values chi subscript upper l superscript 2 and chi subscript upper r superscript 2, and the confidence interval estimate of sigma. it is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. nicotine in menthol cigarettes 98% confidence; nequals28, sequals0.22 mg.

Chi-Square value for lower bond: X²= 46963

Chi-Square value for upper bond: X²= 12.878

Confidence interval:  [0.0278;0.1001]

Step-by-step explanation:

Hello!

You need to make a 98% Confidence interval for the population variance of a single sample. To construct it you have to use a Chi-Square statistic:

X²= (n-1)S² ~X²

         σ²

The formula for the interval is:

Lower bond:

          (n-1)S²                 =           27*0.0484             = 1.3068 = 0.0278

X²       X²       46.963

Upper bond:

          (n-1)S²                 =           2*0.0484               = 1.3068 = 0.1001

X²        X²         12.878

n=28

S= 0.22

S²=0.0484

With a 98% confidence level, you'd expect the true value of the nicotine variance in menthol cigarettes is contained by the interval [0.0278;0.1001]

I hope it helps!

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

its a i did it myself

step-by-step explanation: