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a rectangular pool is surrounded by a walk 2 meters wide. the pool is 3 meters longer than its width. if the total area of the pool and walk is 188 square meters more than the area of the pool, find the dimensions of the pool.

width=20m,length=23m

Step-by-step explanation:

as shown in the figure which is attached

let width of pool =x

⇒ length of pool=x+3

width of walk =2

⇒width of outer boundary of walk=x+4 (2 on each side of pool)

   length of outer boundary of walk=x+3+4=x+7

area of pool =x×(x+3)

area of walk+pool=(x+4)×(x+7)

given

total area of the pool and walk is 188 square meters more than the area of the pool

⇒(x+4)×(x+7)=188+x×(x+3)

⇒8x=160

x=20m

dimensions of pool

widh=20m

length=20+3=23m

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

351.23

step-by-step explanation: