Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. the results from 100 disks are summarized as follows:

shock resistance
scratch resistance high low
high 70 9
low 16 5
let a denote the event that a disk has high shock resistance, and let b denote the event that a disk has high scratch resistance. if a disk is selected at random, determine the following probabilities. input your answers in the fractional form (do not simplify).

p(a)
p(b)
p(a')
p(a u b)
p(a' u b)

P(A) = 86/100

P(B) = 79/100

P(A') = 14/100

P(A U B) = 95/100

P(A' U B) = 84/100

Step-by-step explanation:

i. P(A) = number of disks with high shock resistance/total number of disks

= (70+16)/100

= 86/100

ii. P(B) = number of disks with high scratch resistance/total number of disks

= (70+9)/100

= 79/100

iii. P(A') = number of disks without high shock resistance/total number of disks

= (100-86)/100

= 14/100

iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks

= (70+9+16)/100

= 95/100

v. P(A'UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks

= (5+9+70)/100

= 84/100