For the experiment of rolling an ordinary pair of dice, find the probability that the sum will be less than 3 or greater than 10.

1/9

Step-by-step explanation:

the total number of combinations or outcomes when 2 dice are rolled is 36 ( count all or simply the formula for total number of combinations or outcomes when n dice are rolled is )

sum     possibilities            probability(favorable/ total outcomes of the event)

2          (1,1)                                                       1/36

3          (1,2) , (2,1)                                             2/36

4          (2,2), (3,1) , (1,3)                                    3/36

5          (4,1), (1,4),(2,3),(3,2)                              4/36

6          (1,5),(5,1),(2,4),(4,2),(3,3)                       5/36

7           (2,5),(5,2)(1,6),(6,1),(3,4),(4,3)               6/36

8           (2,6),(6,2), (5,3),(3,5),(4,4)                   5/36

9           (3,6),(6,3),(5,4),(4,5)                            4/36

10          (5,5),(4,6),(6,4)                                   3/36

11            (6,5),(5,6)                                           2/36

12           (6,6)                                                    1/36

probability that the sum will be less than 3 or greater than 10 = probability for sum to be 2 +  probability for sum to be 11 +  probability for sum to be 12

= 1/36 + 2/36 + 1/36

= 4/36

= 1/9

p> q if you calculate p is100 q is 79

d is correct

step-by-step explanation: