Given f(x) equals 3x^3+ kx +16, and x+2 is a factor of f(x), then what is the value of k?

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The Problem:

Given f(x) equals 3x^3+ kx +16, and x+2 is a factor of f(x), then what is the value of k?

Step-by-step explanation:

If x+c is a factor of P then P(-c)=0.

So we are given x+2 is a factor of f so f(-2)=0.

This means we have the following equation:

3(-2)^3+ k(-2) +16=0

Let's solve for k:

3(-8)-2k+16=0

-24-2k+16=0

-8-2k=0

-8=2k

-4=k

k=-4

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

answer: y=0 if that is what u r looking for