The probability a randomly selected residence subscribes to at least one newspaper is 0.38. the probability a randomly selected residence has at least one e-reader is 0.15. assume whether a randomly selected household subscribes to at least one newspaper is independent of whether the residence has at least one e-reader. what is the probability a randomly selected residence subscribes to at least one newspaper given the household has at least one e-reader?

0.38

Step-by-step explanation:

Given that the probability a randomly selected residence subscribes to at least one newspaper is 0.38

The probability a randomly selected residence has at least one e-reader is 0.15

A- subscribes to atleast one newspaper

B = atleast one e reader

A and B are independent

P(A) = 0.38 and P(B) = 0.15

the probability a randomly selected residence subscribes to at least one newspaper given the household has at least one e-reader

= P(A/B) = P(A) (since A and B are independent)

= 0.38

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4