0 (-12,-2)
Mathematics, 06.12.2019 19:31 Melleeroo
What is the center of a circle whose equation is x2 + y2 - 12x – 2y + 12 = 0?
0 (-12,-2)
o (-6, -1)
o (6, 1)
o (12,2)
Answers: 1
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What is the center of a circle whose equation is x2 + y2 - 12x – 2y + 12 = 0?
0 (-12,-2)
0 (-12,-2)
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