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Mathematics, 06.12.2019 20:31 Turtlelover05

The blue diamond company advertises that their nut mix contains (by weight) 40% cashews, 15% brazil nuts, 20% almonds and only 25% peanuts. the truth-in-advertising investigators took a random sample (of size 20 lbs) of the nut mix and found the distribution to be as follows: 5 lbs of cashews, 5 lbs of brazil nuts, 8 lbs of almonds and 2 lbs of peanuts. at the 0.05 level of significance, is the claim made by blue diamond true?
select the [p-value, decision to reject (rh0) or failure to reject (frh0)].

a) [p-value = 0.004, rh0]
b) [p-value = 0.020, rh0]
c) [p-value = 0.041, rh0]
d) [p-value = 0.004, frh0]
e) [p-value = 0.041, frh0]

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The blue diamond company advertises that their nut mix contains (by weight) 40% cashews, 15% brazil...
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