The length of a rectangle is 7 ft longer than twice the width. if the perimeter is 110 ft, find the length and width of the rectangle.

The length of the rectangle is 39 ft

The width of the rectangle is 16 ft

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

The length of a rectangle is 7 ft longer than twice the width. It means that

L = 2W + 7 - - - - - - - - -1

The perimeter of a rectangle is expressed as 2length + 2width

Perimeter = 2(L + W)

If the perimeter is 110 ft, it means that

2(L + W) = 110

L + W = 110/2 = 55 - - - - - - - - -2

Substituting equation 1 into equation 2, it becomes

2W + 7 + W = 55

3W = 55 - 7 = 48

W = 48/3 = 16

L = 55 - W = 55 - 16

L = 39

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]