Find the work done by f in moving a particle once counterclockwise around the given curve. bold upper f equals (5 x minus 4 y )bold i plus (4 x minus 5 y )bold jf=(5x−4y)i+(4x−5y)j c: the circle (x minus 3 )squared plus (y minus 3 )squared equals 9(x−3)2+(y−3)2=9 what is the work done in one counterclockwise

the answer is d. (1.2, -4.7) on edgn

hope this !

24

step-by-step explanation:

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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