Find the equations of the tangents to the given curve that pass through the point (18, 12).

x = 9t2 + 9
y = 6t3 + 6

y = (tangent at smaller t)
y = at larger t)

Step-by-step explanation:

The tangent of a curve is given by the following first degree function:

In which is a function in which the curve pass through and m is the slope, given by the following formula:

In this problem, we have that:

.

So:

And

So:

.

Which means that

The curve passes through (18,12). This means that .

So the equation is:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3