Form a height of 38 meters above sea level, two ships are sighted due west. the angles of depression are 53 degrees and 28 degrees. how far apart are the ships?

d(apart are the ships)=42.8 meters

Step-by-step explanation:

Given data

h (height)=38m

Ф₁=53°

Ф₂=28°

d(how far apart are the ships)=?

Solution

d₅₃°(distance to ship at 53°)=h/tanФ₁

d₅₃°=38/tan(53°)

d₅₃°=28.6m

now

d₂₈°(distance to ship at 28°)=h/tanФ₂

d₂₈°=38/tan(28°)

d₂₈°=71.4m

d(apart are the ships)=d₂₈°-d₅₃°

d(apart are the ships)=71.4-28.6

d(apart are the ships)=42.8 meters

homozygous. one is homozygous, while two is heterozygous.