103^2-102^2=×(103-102)=
pls is in factorization

103^2-102^2  

The property that applies here is a^2-b^2 = (a+b)(a-b)

so the answer is 103^2-102^2=(102+103)*(103-102)= numerically it is 205( as 103+102 = 205 and 103-102 = 1so 205*1 = 205)

The thing is that usually the factorization ends at (102+103)(102-103)

step-by-step explanation:

final answer is : )