Aball left my hand 1.61 m off the ground and after 0.61 seconds the ball reach the maximum height of 3.3 m. use this information to find an equation for the height, h of the ball, in meters, after t seconds

  h = -4.542(t -0.61)² + 3.3

Step-by-step explanation:

The equation of height is presumed to be quadratic, so we can use the vertex form and solve for the scale factor.

  h = a(t -h)² +k . . . . . for vertex (h, k)

Filling in the given values, we can solve for "a":

  1.61 = a(0 -0.61)² +3.3

  (1.61 -3.3)/(0.61²) = a ≈ -4.542

An equation for the height is ...

  h = -4.542(t -0.61)² +3.3

you need a common difference between consecutive terms to be constant, like 1,2,3,4 or 2,4,6,8, or 1,3,6,9