Achemist needs to mix an 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution. how many liters of each of the acid solutions must be used?

This question is based on the system of equation. Therefore, the 8 litres of the 20%  and  7 liters of the 50% solution.

Given:

A chemist needs to mix an 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution.

We need to determined the numbers of liters of each of the acid solutions must be used.

According to the question,

Let the number of liters  be x for 20% and y for the 50% solution.

Then,

⇒ 0.2x + 0.5y = 15 0.34

⇒ 0.2x + 0.5y = 5.1        

Also we have:

Multiply the first equation by -2:

⇒ x    +  y  =  15            

Adding these last 2 equations:

⇒ -0.4x - y = -10.2    

⇒ 0.6x = 4.8

⇒ x = 4.8 / 0.6

⇒ x = 8 and y = 15 - 8 = 7 .

Therefore, the 8 liters of the 20%  and  7 liters of the 50% solution  acid solutions must be used.

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8 litres of the 20%  and

7 litres of the 50% solution.

Step-by-step explanation:

Let the number of litres  be x for 20% and y for the 50% solution. Then

0.2x + 0.5y = 15*0.34

0.2x + 0.5y = 5.1         Also we have:

x      +  y  =  15             Multiply the first equation by -2:

-0.4x - y = -10.2           Adding these last 2 equations:

0.6x = 4.8

x = 4.8 / 0.6

x = 8.

and y = 15 - 8 = 7 .

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