Write and equation in standard form for a line that is (a) parallel (b) perpendicular to the line with an equation of y= 3x - 5 that passes through the point (5,8)

  (a) 3x -y = 7

  (b) x +3y = 29

Step-by-step explanation:

(a) The standard form of the given line is ...

  3x -y = 5

The parallel line will have a constant on the right that makes it go through (5, 8), so it will be ...

  3x -y = 3(5) -(8)

  3x -y = 7

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(b) The perpendicular line will have coefficients for x and y swapped and one of them negated. Again, the constant is chosen to make it go through (5, 8).

  x + 3y = (5) +3(8)

  x + 3y = 29

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752