Paula rows 6 miles upstream in 3 hours she returns downstream in 2 hours. which is the rate paula rows in still water? what is the rate of the current?

her rate in still water is

Step-by-step explanation:

Let x represent the speed of the boat

Let y represent the speed of the current.

Assuming that while she rowed upstream, she rowed in the opposite direction of the current hence, she took longer time. It means her total speed will be x - y

Speed = distance / time

Since she rowed 6 miles upstream in 3 hours, her speed will be 6/3 = 2. Therefore

x - y = 2 - - - - - - - 1

Assuming that while she rowed down, she rowed in the same direction as the current hence, she rowed in still water. It means her total speed will be x + y

Speed = distance / time

Since she rowed 6 miles upstream in 3 hours, her speed will be 6/2 = 3. Therefore

x + y = 3 - - - - - - - 2

Adding equation 1 and equation 2, it becomes

2x = 5

x = 5/2 = 2.5

y = 3 - x = 3 - 2.5

y = 0.5

her rate in still water is x + y = 2.5 + 0.5 = 3 miles per hour

rate of the current is x - y = 2.5 - 0.5 = 2 miles per hour

what do you mean by fog

step-by-step explanation: