The ratio of black pens to blue pens in mark's drawer is 4 to 3. if mark has more than 40 pens, what is the minimun number of pens that can be in mark's drawer?

The minimum number of black pens the drawer is 23 and The minimum number of blue pens in the drawer is 17 .

Step-by-step explanation:

Given as :

The ratio of black pen to blue pen in drawer = 4 : 3

Let The minimum number of black pen = 4 x

And The minimum number of blue pen = 3 x

The total number of pens in drawer = more than 40

So, According to question

∵ The total number of pens in drawer 40

So, 4 x + 3 x 40

Or, 7 x 40

∴ x

I.e x   5.71

So,  The minimum number of black pen = 4 × 5.7 = 22.8 ≈ 23

And  The minimum number of blue pen = 3 × 5.7 = 17.1 ≈ 17

Hence The minimum number of black pens the drawer is 23 and The minimum number of blue pens in the drawer is 17 . Answer

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

the answer is 1030 it's very simple math.