Determine the total revenue earned by selling x calculator if the price per calculator is given by the demand function p = 150 - 0.4x. how many calculators must be sold to maximize the total revenue?

The revenue is maximum around 187.5 that means we can sell 187 or 188 calculators to get the maximum revenue.

Step-by-step explanation:

Let the total number of calculators sold = x

The price per demand of calculator , p =150 - 0.4x

Total revenue =

                        =

To maximize revenue, derivative of total revenue must be zero.

= 0

150 - 0.4x - 0.4x = 0

150 - 0.8x = 0

0.8x = 150

x = 187.5

So the revenue is maximum around 187.5 that means we can sell 187 or 188 calculators to get the maximum revenue.

Maximum revenue =

                                =14,062.4

x/3-10=8

x/3=18

x=48

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.