In the figure, what is the area of triangle $abd$? express your answer as a common fraction. [asy] draw((34)); draw((0,,0)); ,,.,.5)); label("$a$",(0,4),w); label("2",(0,3),w); label("$e$",(0,2),w); label("2",(0,1),w); label("$c$",(0,0),sw); label("3",(1.5,0),s); label("$f$",(3,0),s); label("4",(5,0),s); label("$b$",(7,0),se); label("$d$",(21/11,16/11),ne); [/asy]

b. x- 48 =120

step-by-step explanation:

answer:

c. the third graph

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

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step-by-step explanation: