Adilation has center at the origin. which of the following is the image of the point pc - 3) for a scale
factor of

The image of the point p is p'(\frac{1}{4},\frac{-5}{14}).

Step-by-step explanation:

The center of dilation is origin and the scale factor is \frac{1}{7}.

The coordinates of point p are

(\frac{7}{4},\frac{-5}{2})

If k is the scale factor and origin is the center of dilation, then

(x,y)\rightarrow (kx,ky)

Since the scale factor is \frac{1}{7} and the origin is the center of dilation, therefore

(x,y)\rightarrow (\frac{1}{7}x,\frac{1}{7}y)

The coordinates of image of p are

p(\frac{7}{4},\frac{-5}{2})\rightarrow p'(\frac{1}{7}\times \frac{7}{4},\frac{1}{7}\times \frac{-5}{2})

p(\frac{7}{4},\frac{-5}{2})\rightarrow p'(\frac{1}{4},\frac{-5}{14})

Therefore the image of the point p is p'(\frac{1}{4},\frac{-5}{14}).

Step-by-step explanation: hope this helps mark me as brainiest

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step-by-step explanation: