Find an equation perpendicular to the line -4x+5 and passes through points (-2,-6)

find an equation of the line that is parallel to this line and passes through the point (-2,-6)

need an answer asap

1. y = 1/4x - 11/2

2. y = -4x - 14

Step-by-step explanation:

If two lines are perpendicular, the slopes should be reciprocals and negatives of each other. (for example, 3/2 becomes -2/3, or -7/5 becomes 5/7)

The slope of -4x + 5 is -4. So the new line's slope will be 1/4.

Now the equation is y = 1/4x + b. To find b, substitute (-2,-6).

y = 1/4x + b

-6 = 1/4(-2) + b

-6 = -1/2 + b

-11/2 = b

So equation is y = 1/4x - 11/2

2.

If two lines are parallel, their slopes are the same.

So the new equation is y = -4x + b

To find b, substitute (-2,-6)

y = -4x + b

-6 = -4(-2) + b

-6 = 8 + b

-14 = b

So equation is y = -4x - 14

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6