The placement test for a college has scores that are normally distributed with a mean of 600 and a standard deviation of 50. if the college accepts only the top 14% of examinees, what is the cutoff score on the test for admission?

The cut-off score on the placement test for the college is 654 points

Step-by-step explanation:

1. Let's review the information given to answer the question correctly:

Mean of the scores of the placement test for a college = 600 points

Standard deviation = 50

College only accepts the top 14% of the examinees

Probability is (1 - 0.14) = 0.86

2. Let's calculate the value of z-score, using the z-table:

z-score for .8599 (rounding to .86) is 1.08

Replacing with the real values, we have:

Standard deviation for .8599 (rounding to .86) is:

50 * 1.08 = 54

Cut-off score on the placement test = 600 + 54

The cut-off score on the placement test for the college is 654 points

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

(x) - (y) = (1 + 4i)