And answer! i do not understand! will mark !

5) The common difference is

6)a)

  b)

Step-by-step explanation:

5) It is given  that 10th term is 17 and  14th term is 30.

for any general arithmetic series, the nth term is given by

, a= first term and d= common difference.

Inserting both the conditions above, we get

,

solving the above equations we get,

(common difference)

6) a) a(18) =3362  and a(38) = 7362

       a(18) = a + (17)(d) = 3362  and a(38) = a + (37)(d) = 7362

Solving the above equation we get, a= -138 and d= 200.

b) a(18) = 44.3   and   a(33) = 84.8

    a(18) = a + (17)(d) = 44.3    and   a(33) = a + (32)(d) = 84.8

Solving the above equation we get, a= -1.6 and d= 2.7

you are uyytr tyy

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb