Question 4 (6 points)
a company imports olive oil and wants to determine whether they are supplying the correct amount at the correct price. they
don't want to have overstock since they don't have a storage facility. also, they want to sell as much as possible at the highest
price possible!
given the two supply and demand equations where qs is the quantity supplied at a given price (p) and qd is the quantity
demanded at a certain price (p), determine (algebraically) the equilibrium point. interpret the equilibrium point by stating the
selling price and supply in the market when supply and demand are in equilibrium.
qs(p) = 6p + 530
qd(p) = -8p + 740
show all the steps of your work (can paste an image of your work) and explanation in the space provided.

6.5

step-by-step explanation:

you said it was in the question

~courtney

i would you but i don't under stand the qustion

step-by-step explanation:

b. b < 1 might be the correct answer

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.